(n^3+n+10)/(n-2)

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Solution for (n^3+n+10)/(n-2) equation: 


D( n )

n-2 = 0

n-2 = 0

n-2 = 0

n-2 = 0 // + 2

n = 2

n in (-oo:2) U (2:+oo)

(n^3+n+10)/(n-2) = 0

n^3+n+10 = 0

n^3+n+10 = 0

{ 1, -1, 2, -2, 5, -5, 10, -10 }

1

n = 1

n^3+n+10 = 12

1

-1

n = -1

n^3+n+10 = 8

-1

2

n = 2

n^3+n+10 = 20

2

-2

n = -2

n^3+n+10 = 0

-2

n+2

n^2-2*n+5

n^3+n+10

n+2

-n^3-2*n^2

n-2*n^2+10

2*n^2+4*n

5*n+10

-5*n-10

0

n^2-2*n+5 = 0

DELTA = (-2)^2-(1*4*5)

DELTA = -16

DELTA < 0

n in { -2} 

n+2 = 0

(n+2)/(n-2) = 0

n+2 = 0 // - 2

n = -2

n = -2

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